∫
f′(x)
π
Σ
Δx
√
cos(θ)
∂y/∂x
y = f(x)
f′(x) = lim[h→0] [f(x+h) - f(x)]/h
∫ f(x) dx = F(x) + C
d/dx[sin(x)] = cos(x)
d/dx[cos(x)] = -sin(x)
d/dx[e^x] = e^x
d/dx[ln(x)] = 1/x
d/dx[x^n] = nx^(n-1)
d/dx[f(x)g(x)] = f′(x)g(x) + f(x)g′(x)
d/dx[f(g(x))] = f′(g(x))g′(x)
∫ x^n dx = x^(n+1)/(n+1) + C
∫ e^x dx = e^x + C
∫ 1/x dx = ln|x| + C
∫ sin(x) dx = -cos(x) + C
∫ cos(x) dx = sin(x) + C
الحصة الأولى من المكثف
الاشتقاق
( وَمَنْ يَتَوَكَّلْ عَلَى اللَّهِ فَهُوَ حَسْبُهُ )